A time dependent force F = 10 t is applied on 10 kg block. Find out the work done by F in 2 seconds.

A force $F=(3{x}^{2}+2x-7)N$ acts on a $2kg$ body as a result of which the body gets displaced from $x=0$ to $x=5m$. The work done by the force will be:

A particle moves along X-axis from $x = 0$ to $x = 5\ m$ under the influence of force given by $F = (7 - 2x + 3x^{2}) N$. The work done in the process is

A body of mass$; 3$kg is under a force, which causes a displacement& ; in it is given by $S=\frac{t^{3}}{3} \underline{(i n m)}$

find the work done by the force in first $2$ seconds

Under influence of a force $\overrightarrow { F } \left( x \right) =\left( 3{ x }^{ 2 }-2x+5 \right) \hat { i } N$ there is displacement of a particle from $x=0$ and $x=5m$ on $x-$axis. So work done is $J$.