cosθ + √3 sinθ = 2 সমীকরণের সাধারণ সমাধান-

দেওয়া আছে,

$\cos\theta+\sqrt{3}sin\theta=2$

$\Rightarrow \frac{1}{2}cos\theta + \frac{\sqrt{3}} {2} sin\theta =1$

$\Rightarrow cos\frac{\pi}{3} cos\theta + sin\frac{\pi}{3} sin\theta =1$

$\Rightarrow cos(\theta -\frac{\pi}{3})=1$

$\Rightarrow \theta -\frac{\pi}{3}=2 n \pi$

$\therefore \theta= 2 n \pi + \frac{\pi}{3}$