সংযোজিত ফংশন

f(x)=x2+2f\left(x\right)=x^2+2g(x)=sin(ax)g\left(x\right)=\sin(ax) এবং fog(π6)=114fog\left(\frac{\pi}{6}\right)=\frac{11}{4} হলে, a = ?

{sin(a×π6)}2+2=114 sinπa6=32πa6=π3a=2\left\{\sin{\left(a\times\frac{\pi}{6}\right)}\right\}^2+2=\frac{11}{4}\ \Rightarrow\sin{\frac{\pi a}{6}}=\frac{\sqrt3}{2}\Rightarrow\frac{\pi a}{6}=\frac{\pi}{3}\therefore a=2

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