মান নির্ণয়
If tan x=b/a, then value of (a2+ b²) sin 2x is-
2ab
Solution: (a);(a2+b2)sin2x=(a2+b2)⋅2tanx1+tan2x=(a2+b2)×2×ba1+b2a2=(a2+b2)×2×baa2+b2a2=2ab (a) ;\left(a^{2}+b^{2}\right) \sin 2 x=\left(a^{2}+b^{2}\right) \cdot \frac{2 \tan x}{1+\tan ^{2} x}=\left(a^{2}+b^{2}\right) \times \frac{2 \times \frac{b}{a}}{1+\frac{b^{2}}{a^{2}}}=\left(a^{2}+b^{2}\right) \times \frac{2 \times \frac{b}{a}}{\frac{a^{2}+b^{2}}{a^{2}}}=2 a b (a);(a2+b2)sin2x=(a2+b2)⋅1+tan2x2tanx=(a2+b2)×1+a2b22×ab=(a2+b2)×a2a2+b22×ab=2ab
tanθ=p হলে, cos2θ= কত? \tan \theta=p \text { হলে, } \cos 2 \theta=\text { কত? } tanθ=p হলে, cos2θ= কত?
যদি π2<θ<πএবংsinθ=35হয়, \frac{\pi}{2} < \theta < \pi এ ব ং \sin{\theta} = \frac{3}{5} হ য় , 2π<θ<πএবংsinθ=53হয়, তবে cosθ এর মান কত?
tan105∘=tan(60∘+45∘)\tan 105^{\circ}=\tan \left(60^{\circ}+45^{\circ}\right)tan105∘=tan(60∘+45∘) এর মান কত?
If cosθ=513\displaystyle \cos \theta =\frac{5}{13}cosθ=135, where θ\theta θ being an acute angle, then the value of cosθ+5cotθcosec θ−cosθ\dfrac{\cos \theta +5\cot \theta }{\text {cosec}\ \theta -\cos \theta }cosec θ−cosθcosθ+5cotθ will be