Determining different elements of parabola

If the parabola y2=4ax{y^2} = 4\,\,ax passes through the point (3,2),\left( { - 3,2} \right), then the length of its latus rectum is-

y2=4ax(3,2)4=4×ax3a=1/3 \begin{array}{l} y^{2}=4 a x \\ (-3,2) \rightarrow 4=4 \times a x-3 \\ \therefore a=-1 / 3 \end{array}

\therefore latus rectum 4a=43 |4 a|=\frac{4}{3}

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