জটিল সংখ্যা

If z be a complex number satisfying z4+z3+2z2+z+1=0\displaystyle\ z^{4}+z^{3}+2z^{2}+z+1=0 then  z\displaystyle\ |z| is 

কাজু বাদাম

z4+z3+2z2+z+1=0{ z }^{ 4 }+{ z }^{ 3 }+2{ z }^{ 2 }+z+1=0

[z4+2z2+1]+[z3+z]=0\left[ { z }^{ 4 }+2{ z }^{ 2 }+1 \right] +\left[ { z }^{ 3 }+z \right] =0

[z2+1][z2+1+z]=0\left[ { z }^{ 2 }+1 \right] \left[ { z }^{ 2 }+1+z \right] =0

z2+1=0z=±i{ z }^{ 2 }+1=0\Longrightarrow z=\pm i

z=1\left| z \right| =1

or

z2+z+1=0{ z }^{ 2 }+z+1=0

z=1±142=1±3i2z=\cfrac { -1\pm \sqrt { 1-4 } }{ 2 } =\cfrac { -1\pm \sqrt { 3i } }{ 2 }

z=14+34=1\left| z \right| =\sqrt { \cfrac { 1 }{ 4 } +\cfrac { 3 }{ 4 } } =1

z=1\therefore \boxed { \left| z \right| =1 }

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