কির্শফের সূত্র
In L-C-R circuit power of 3 mH inductance and 4Ω4\Omega4Ω resistance, EMF E=4 cos 1000tE=4\,cos\,1000tE=4cos1000t volt is applied. The amplitude of current is
0.8A˚0.8\mathring{A}0.8A˚
47A˚\dfrac{4}{7}\mathring{A}74A˚
1.0A˚1.0\mathring{A}1.0A˚
47A˚\dfrac{4}{\sqrt{7}}\mathring{A}74A˚
Impedance of inductor=XL=ωH=1000×3mH=3ΩX_L=\omega H=1000\times 3mH=3\OmegaXL=ωH=1000×3mH=3Ω
Thus the impedance of the circuit=X=XL2+R2=5ΩX=\sqrt{X_{L}^2+R^2}=5\OmegaX=XL2+R2=5Ω
Thus amplitude of current Imax=EmaxX=4V5Ω=0.8AI_{max}=\dfrac{E_{max}}{X}=\dfrac{4V}{5\Omega}=0.8AImax=XEmax=5Ω4V=0.8A
চিত্র-১ এ পরিবাহীটির অংশ্ 20 molee 20 \mathrm{~mole} \mathrm{e} 20 molee আছে যার তাড়ন বেগ v=2.8×108 \mathrm{v}=2.8 \times 10^{8} v=2.8×108 ms−1 \mathrm{ms}^{-1} ms−1
Find the currents I1I_1I1 and I2I_2I2 for the circuit shown in given figure.
Kirchhoff's Loop rule is a direct consequence of law of conservation of
Kirchoff's voltage law and current law are respectively in accordance with the conservation of-