রোধ

In the network shown in the figure, the equivalent resistance between A and C is

হানি নাটস

$2R, R$ and $3R$ are in parallel, as they all are between same potential
$\dfrac{1}{R}+\dfrac{1}{2R}+\dfrac{1}{3R}-\dfrac{1}{R_p}\Rightarrow \dfrac{1}{R_p}=\dfrac{6+3+2}{6R}=\dfrac{11}{6R}$
$\dfrac{6R}{11}$ and $4R$ is in parallel, so
$\dfrac{6R}{11}+4R=\dfrac{6R+44R}{11}=\left(\dfrac{50}{11}\right)R$
$\boxed{Req_0=\left(\dfrac{50}{11}\right)R}$

রোধ টপিকের ওপরে পরীক্ষা দাও

এখনো না বুঝতে পারলে ডাউটস এ পোস্ট করো

পোস্ট করো

Related question

When temperature of the conductor is increased, then the collision frequency between current carries ( electrons ) and atoms increases. This results in

$10$ wires (same length, same area, same material) are connected in parallel and each has $1\Omega$ resistance, then the equivalent resistance will be

The voltage - current $(V-I)$ graph of a metallic conductor at two different temperature $T_{1}$ and $T_{2}$ is shown below. At which temperature is the resistance higher?

Six identical cells, each of emf of $6V$ , are connected in parallel. The net emf across the battery is