লিমিট
limx→0sin2xxcos3x \lim _{x \rightarrow 0} \frac{\sin 2 x}{x \cos 3 x} limx→0xcos3xsin2x এর মান-
333
222
23\frac{2}{3}32
12\frac{1}{2}21
limx→0sin2xxcos3x=limx→0sin2x2x×2×1cos3x=1×2×11=2 \begin{aligned} & \lim _{x \rightarrow 0} \frac{\sin 2 x}{x \cos 3 x} \\ = & \lim _{x \rightarrow 0} \frac{\sin 2 x}{2 x} \times 2 \times \frac{1}{\cos 3 x} \\ = & 1 \times 2 \times \frac{1}{1} \\ = & 2\end{aligned} ===x→0limxcos3xsin2xx→0lim2xsin2x×2×cos3x11×2×112
If the function f(x)=(1−x)tanπx2f(x) = (1 - x)\tan \dfrac{{\pi x}}{2}f(x)=(1−x)tan2πx is continuous at x=1x = 1x=1 ,then f(1)=f(1)=f(1)=
limx→0xtan2x−2xtanx(1−cos2x)2 \displaystyle \lim _{x \rightarrow 0} \dfrac{x \tan 2 x-2 x \tan x}{(1-\cos 2 x)^{2}} x→0lim(1−cos2x)2xtan2x−2xtanx is equal to
এর সঠিক মান কোনটি?
নিচের সীমার মান কোনটি? limx→ysinx−sinyx−y\lim _{x \rightarrow y} \frac{\sin x-\sin y}{x-y}limx→yx−ysinx−siny