সমীকরণ সমাধান
tancot-1tancos-1x এর মান কত?
x
tancot−1tancos−1x=tancot−1tan(tan−11−x2x) \tan \cot ^{-1} \tan \cos ^{-1} \mathrm{x}=\tan \cot ^{-1} \tan \left(\tan ^{-1} \frac{\sqrt{1-\mathrm{x}^{2}}}{\mathrm{x}}\right) tancot−1tancos−1x=tancot−1tan(tan−1x1−x2)
=tancot−11−x2x=tantan−1x1−x2=x1−x2 =\tan \cot ^{-1} \frac{\sqrt{1-x^{2}}}{x}=\tan \tan ^{-1} \frac{x}{\sqrt{1-x^{2}}}=\frac{x}{\sqrt{1-x^{2}}} =tancot−1x1−x2=tantan−11−x2x=1−x2x
f(x)=sinx \mathrm{f}(x)=\sin x f(x)=sinx এবং g(x)=cosx g(x)=\cos x g(x)=cosx.
3sec-1(2)=cos-1x হলে x এর মান ত?
cosθ=12 \cos{θ} = \frac{1}{\sqrt{2}} cosθ=21 হলে,θ এর মান কত?
2tan−1(abtanθ2)=?2 \tan ^{-1}\left(\sqrt{\frac{a}{b}} \tan \frac{\theta}{2}\right) = ? 2tan−1(batan2θ)=?
