The area, in square units of the region bounded by the parabolas $y^{2}=4x$ and $x^{2}=4y$ is

$Letf(x)={ sin }^{ -1 }(sin\quad x)+{ cos }^{ -1 }(\quad cos\quad x),\quad g(x)=mx\quad and\quad h(x)=x\quad$ are three functions. Now g(x) is divided area between f(x),x=$\pi$ and y=0 into two equal parts.

The area bounded by the curve y=f(x), x=$\pi$ and y=0 is:

Semicircles are drawn outside by taking every side of regular hexagon as a diameter. The ;perimeter of hexagon is 60 cm. Find the area of complete figure formed as such.($\pi$ = 3.14) ($\sqrt3$ = 1.73)

দৃশ্যকল্প-১: $f(x)=x+1, g(x)=x-1, h(x)=x^{2}+9$

দৃশ্যকল্প-২: $y=\cos x$

The area ehclosed by the curves y = f(x) and ; y =g(x), where f(x) = max ${x , x^2}$ and g(x) = min ${x, x^2}$ opver the interval [0,1] is& ;