1. Scenario-1: 9y2−16x2−64x−54y−127=0 9 y^{2}-16 x^{2}-64 x-54 y-127=0 9y2−16x2−64x−54y−127=0
Find the equation of the directrices of the ellipse 5x2+4y2=1.2 5 x^{2}+4 y^{2}=1.2 5x2+4y2=1.2
Using scenario-1, find the coordinates of the foci, distance between their foci and length of the latus rectum.
From scenario-2, find the equation of MZM'.
2. Scenario-2 : A bag contains 7 red, 5 black and 4 white balls. Three balls are drawn at random.
P(A)=13,P(B)=16 P(A)=\frac{1}{3}, P(B)=\frac{1}{6} P(A)=31,P(B)=61 if A A A and B B B are independent events. Then find P(A/B) P(A / B) P(A/B).
Find the variance from the frequency distribution table maintained in the scenario-1.
From scenario-2, find the probability to getting at least 2 red balls.
3. Scenario-1 : g(x)=11−9x+20x2 g(x)=\frac{1}{1-9 x+20 x^{2}} g(x)=1−9x+20x21
Scenario-2 : mx2+nx+s=0 m x^{2}+n x+s=0 mx2+nx+s=0 is quadratic equation.
Determine the argument of the complex number −4−4i -4-4 i −4−4i.
Using scenario-1, find the coefficient of xn x^{n} xn in the expansion of g(x) g(x) g(x).
Using scenario-2, if m=9,n=2,s=−13(p+2) m=9, n=2, s=-\frac{1}{3}(p+2) m=9,n=2,s=−31(p+2) and one root of the given equation is square of the other. Then find the value of p p p.
4. Scenario-1: f(a)=sec−11a+sec−11b f(a)=\sec ^{-1} \frac{1}{a}+\sec ^{-1} \frac{1}{b} f(a)=sec−1a1+sec−1b1
Scenario-2 : g(α)=sin(πcosα)−cos((πsinα) g(\alpha)=\sin (\pi \cos \alpha)-\cos ((\pi \sin \alpha) g(α)=sin(πcosα)−cos((πsinα).
Find the value of cot(sin−115) \cot \left(\sin ^{-1} \frac{1}{\sqrt{5}}\right) cot(sin−151).
From scenario-2, if g(α)=0 g(\alpha)=0 g(α)=0 then show that, α=±12sin−134 \alpha= \pm \frac{1}{2} \sin ^{-1} \frac{3}{4} α=±21sin−143,
Using scenario-1, if f(a)=α f(a)=\alpha f(a)=α then prove that, sinα= \sin \alpha= sinα= a2+b2−2abcosα \sqrt{a^{2}+b^{2}-2 a b \cos \alpha} a2+b2−2abcosα
5. Scenario-1 : The roots of 8x2−6x+1=0 8 x^{2}-6 x+1=0 8x2−6x+1=0 are a a a and b b b. Scenario-2 : (1+3y)2n (1+3 y)^{2 n} (1+3y)2n where n∈Z n \in \mathbb{Z} n∈Z.
Find the value of i3 \sqrt[3]{i} 3i.
With the help of the scenario-1, find the equation whose roots are a+1 b \mathrm{a}+\frac{1}{\mathrm{~b}} a+ b1 and b+1a \mathrm{b}+\frac{1}{\mathrm{a}} b+a1.
Show that the expansion of scenario- 2 the coefficient of the middle term is 1⋅3.5⋯(2n−1)n!6nyn \frac{1 \cdot 3.5 \cdots(2 n-1)}{n !} 6^{n} y^{n} n!1⋅3.5⋯(2n−1)6nyn