1. a=4,b=−4,z=1n(1+im) a=4, b=\sqrt{-4}, z=\frac{1}{n}(1+i m) a=4,b=−4,z=n1(1+im) is a complex number.
Express 2−3i4−4i \frac{2-3 i}{4-4 i} 4−4i2−3i in the form of A+iB A+i B A+iB.
Find the value of a+b \sqrt{a+b} a+b.
If 1=m=3 1=m=3 1=m=3 and n=18 n=\sqrt{18} n=18, then determine the sum of cube roots of ∣2∣ |2| ∣2∣.
2. f1(x)=4x2−7x+3f2(x)=ax2+βx+γ \begin{array}{l} f_{1}(x)=4 x^{2}-7 x+3 \\ f_{2}(x)=a x^{2}+\beta x+\gamma \end{array} f1(x)=4x2−7x+3f2(x)=ax2+βx+γ
Find the modulus and principal argument Chopters \& −4+4i -4+4 \mathrm{i} −4+4i.
If one root of the equation f2(x)=0 f_{2}(x)=0 f2(x)=0 is the square of the other, then find the value of a a a, where α=9 \alpha=9 α=9, β=2 \beta=2 β=2 and γ=−13(a+2) \gamma=-\frac{1}{3}(a+2) γ=−31(a+2).
If p,q \mathrm{p}, \mathrm{q} p,q are the roots of the equation f1(x)=0 f_{1}(\mathrm{x})=0 f1(x)=0, then form the equation whose roots are 1p \frac{1}{p} p1 and 1q34 \frac{1}{q^{3}} \quad 4 q314
3. f(x)=x2−4x+5g(x)=x+1φ(x)=1x2+mx+nψ(x)=nx2+mx+1 \begin{array}{l} f(x)=x^{2}-4 x+5 \\ g(x)=x+1 \\ \varphi(x)=1 x^{2}+m x+n \\ \psi(x)=n x^{2}+m x+1 \end{array} f(x)=x2−4x+5g(x)=x+1φ(x)=1x2+mx+nψ(x)=nx2+mx+1
Show that, the roots of the equation 2x2+6x−8= 2 x^{2}+6 x-8= 2x2+6x−8= 0 are rational.
If the equations φ(x)=0 \varphi(x)=0 φ(x)=0 and ψ(x)=0 \psi(x)=0 ψ(x)=0 have a common root, then express m m m in terms of l l l and n n n.
If the roots of the equation f(x)⋅g(x)=0 f(x) \cdot g(x)=0 f(x)⋅g(x)=0 are p,q p, q p,q, r r r, then find the value of symmetric expression Σp3q \Sigma p^{3} q Σp3q.
4. Scenario-1: A swimmer takes t1 t_{1} t1 second to cross a river directly. It takes t2 t_{2} t2 seconds to cover the same distance along the rive bank in favour of the current.
Scenario-2:
An object starts from the rest moves to the uniform acceleration 3 m/s2 3 \mathrm{~m} / \mathrm{s}^{2} 3 m/s2. After how long time its velocity will be 60 m/s 60 \mathrm{~m} / \mathrm{s} 60 m/s ?
According to the secnario-1, if the speed of the swimmer 20 cm/s 20 \mathrm{~cm} / \mathrm{s} 20 cm/s and the current is 10 cm/s 10 \mathrm{~cm} / \mathrm{s} 10 cm/s, then determine t1:t2 t_{1}: t_{2} t1:t2.
According to the scenario-2, if OA=49 \mathrm{OA}=49 OA=49 meter, then find the distance of OB O B OB the question no. 3
5.
Find the magnitude of the resultant of two equal forces P P P acting at a point inclined at angle α \alpha α to each other.
If two like parallel forces as shown in scenario-1 interchange with each other, the action point of resultant is moved to a distance d d d along AB A B AB. Prove that, d=107 \mathrm{d}=\frac{10}{7} d=710 meter.
In scenario-2, if P=6 N,Q=9 N P=6 \mathrm{~N}, \mathrm{Q}=9 \mathrm{~N} P=6 N,Q=9 N and R=5 N \mathrm{R}=5 \mathrm{~N} R=5 N, then find the magnitude and direction of the resultant of forces.