A force $F=(3{x}^{2}+2x-7)N$ acts on a $2kg$ body as a result of which the body gets displaced from $x=0$ to $x=5m$. The work done by the force will be:

A body of mass$; 3$kg is under a force, which causes a displacement& ; in it is given by $S=\frac{t^{3}}{3} \underline{(i n m)}$

find the work done by the force in first $2$ seconds

Under influence of a force $\overrightarrow { F } \left( x \right) =\left( 3{ x }^{ 2 }-2x+5 \right) \hat { i } N$ there is displacement of a particle from $x=0$ and $x=5m$ on $x-$axis. So work done is $J$.

A force of $\left(4 x^{2}+3 x\right)$ N acts on a particle which displaces it from $x=2 m$ to $x=3 \mathrm{m}$.

The work done by the force is

The work done by a force $\vec{F}=\left ( -6x^3\hat{i} \right )\ N$ is displacing a particle from $x=4\ m$ to $x=-2\ m$ is