সরল দোলন গতি

A set of keys on the end of a string is swung steadily in a horizontal circle. In one trial, it moves at speed vv in a circle of radius rr. In a second trial, it moves at a higher speed 4v4v in a circle of radius 4r4r. In the second trial, how does the period of its motion compare with its period in the first trial?

হানি নাটস

Write the expression for the period of the horizontal circular motion of the keys.

T=2πrv T=\frac{2 \pi r}{v}

Here, T T is the period of the horizontal circular motion of the keys, r r is the radius of the circular path and v v is the speed of the keys.

Conclusion:

Substitute 4v 4 v for v v and 4r 4 r for r r in (I) for the second trial period of the key T2 T_{2}

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