রোধ

An alternating voltage $E=200 \sin (300 t)$ volt is applied across a series combination of $R=10 \Omega$ and inductance of $800\ mH$ . Calculate the impedance of the circuit.

Given : $L = 800 \ mH$ $R = 10\Omega$
Alternating source voltage $E = 200 \ \sin(300 t)$
Comparing with $E = E_o\ sin wt$
we get $w = 300$
Inductive reactance $X_L = wL = 300\times 800\times 10^{-3} = 240 \ \Omega$
Impedance of the circuit $Z = \sqrt{R^2+X_L^2}$
$\implies \ Z = \sqrt{10^2+240^2} = 240.21\Omega$

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