An alternating voltage$E=200 \sin (300 t)$ volt is applied across a series combination of $R=10 \Omega$ and inductance of $800\ mH$. Calculate the impedance of the circuit.

Given : $L = 800 \ mH$ $R = 10\Omega$

Alternating source voltage $E = 200 \ \sin(300 t)$

Comparing with $E = E_o\ sin wt$

we get $w = 300$

Inductive reactance $X_L = wL = 300\times 800\times 10^{-3} = 240 \ \Omega$

Impedance of the circuit $Z = \sqrt{R^2+X_L^2}$

$\implies \ Z = \sqrt{10^2+240^2} = 240.21\Omega$