At a point very near to the earth's surface, the acceleration due to gravity is g. What will be the acceleration due to gravity at the same point if the earth suddenly shrinks to half its radius without any change in its mass?

In the figure it is shown that the velocity of lift is ;$2\;{\text{m}}{{\text{s}}^{{\text{ - 1}}}}$ while string ins winding on the motor shaft with velocity $2\;{\text{m}}{{\text{s}}^{{\text{ - 1}}}}$ and shaft A is moving downward with velocity $2\;{\text{m}}{{\text{s}}^{{\text{ - 1}}}}$ with respect lift, then find out the velocity of block B

At what height from the ground will be the value of $g$ be the same as

that in $10 km$ deep mine below the surface of earth.

The value of acceleration due to gravity on earth surface-

Gravity meters measures in units of mGal where 1 Gal (or 1 galileo) is the C.G.S unit of acceleration due to gravity. A gravity meter shows a reading of +300 mGal at a place where the normal 'g' is 9.78 $m s^{-2}$. The correct 'g' at that place where the reading was taken is _____ $m s^{-2}$.