মান নির্ণয়

cos(45°+θ)cos(45°-θ)-sin(45°+θ)sin(45°-θ)=কত? 

cos(45+θ)cos(45θ)sin(45+θ)sin(45θ)=cos(45+θ+45θ)=cos90=0 \begin{array}{l} \cos \left(45^{\circ}+\theta\right) \cdot \cos \left(45^{\circ}-\theta\right)-\sin \left(45^{\circ}+\theta\right) \cdot \sin \left(45^{\circ}-\theta\right) \\ =\cos \left(45^{\circ}+\theta+45^{\circ}-\theta\right) \\ =\cos 90^{\circ} \\ =0 \end{array}

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