কাজ

How much work must be done by a force on 50 50\ kgkg body in order to accelerate it from rest to 20 m/s20\ m/s in 10 10\ ss ?

হানি নাটস

Acceleration that causes the given rise in speed in given time = a=vt=20 m/s10 s=2 m/s2a=\dfrac{v}{t}=\dfrac{20\ m/s}{10\ s}=2\ m/s^2

Thus, force acting on the body = F=ma=100 NF=ma=100\ N

Distance travelled in the given time = s=12at2=100 ms=\dfrac{1}{2}at^2=100\ m

Thus, work done in given time = F.s=104 JF.s=10^4\ J

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