If the roots of the equation $2x^2-3x + c = 0$ are real and irrational, a possible value of c is

Real, irrational

$b^{2}-4 a c>0$

Given, $2 x^{2}- 3 x+c=0$.

$\begin{array}{c} (-3)^{2}-4 \cdot 2 \cdot c \geq 0 \\ c \leq \frac{9}{8} \end{array}$

condition for irrotational

Roots: For roots to be irrotational discriminant must not be perfect square. Thus $9-8 c$ should not be a perfect square.

let $c=1 \quad 9-8.1=9.8=1$ This is a perfect square. So $c=1$ is not per suitable

let. $c=-1$.

$9-8(-1)=17$

The value 17 is not a perfect square so,

$C=-1$