In an ac circuit, the resistance of R $\Omega$ is connected in series with an inductance $I$. If phase angle between voltage and current be $\displaystyle 45^{\circ}$, the value of inductive reactance will be:

When temperature of the conductor is increased, then the collision frequency between current carries ( electrons ) and atoms increases. This results in

$10$ wires (same length, same area, same material) are connected in parallel and each has $1\Omega$ resistance, then the equivalent resistance will be

A wire has resistance of $12 \Omega$. It is cut into two parts and both have are connected in parallel. The new resistance is?

The voltage - current $(V-I)$ graph of a metallic conductor at two different temperature $T_{1}$ and $T_{2}$ is shown below. At which temperature is the resistance higher?