অভিকর্ষ ও অভিকর্ষজ ত্বরণ

In the figure it is shown that the velocity of lift is ;2  ms - 12\;{\text{m}}{{\text{s}}^{{\text{ - 1}}}} while string ins winding on the motor shaft with velocity 2  ms - 12\;{\text{m}}{{\text{s}}^{{\text{ - 1}}}} and shaft A is moving downward with velocity 2  ms - 12\;{\text{m}}{{\text{s}}^{{\text{ - 1}}}} with respect lift, then find out the velocity of block B

হানি নাটস

Lift =2=2 m/s

velocity =2=2 m/s

down ward velocity =2=2 m/s

\therefore velocity of Block B=2+22B=\uparrow 2+2\uparrow -2\downarrow

=42=4-2

=42=4-2

=2m/s=2m/s\uparrow

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