নির্দিষ্ট যোগজ
√3
√2
4
4√2
∫0π1−cosx3sinxdx=1−cosx3sinxdx=3∫tdt ;t=1−cosx \begin{array}{l}\int_{0}^{\pi} \sqrt[3]{1-\cos x} \sin x d x \\ =\sqrt[3]{1-\cos x} \sin x d x \\ =3 \int \sqrt{t} d t~~~ ; t=1-\cos x \\\end{array} ∫0π31−cosxsinxdx=31−cosxsinxdx=3∫tdt ;t=1−cosx
=3×2t×t3=[21−cosx×(1−cosx)]0π=42 \begin{array}{l}=3 \times \frac{2 \sqrt{t} \times t}{3} \\ =[2 \sqrt{1-\cos x} \times(1-\cos x)]_{0}^{\pi} \\ =4 \sqrt{2}\end{array} =3×32t×t=[21−cosx×(1−cosx)]0π=42
∫0π4cosθcos2θdθ=? \int_{0}^{\frac{\pi}{4}} \frac{\cos \theta}{\cos ^{2} \theta} d \theta=? ∫04πcos2θcosθdθ=?
The value of ∫−π/2199π/2(1+cos2x)dx\displaystyle\int^{199\pi/2}_{-\pi/2}\sqrt{(1+\cos 2x)}dx∫−π/2199π/2(1+cos2x)dx is?
∫0π/2cosxdx= কত? \int_{0}^{\pi / 2} \cos x d x=\text { কত? } ∫0π/2cosxdx= কত?
∫0π6sin2xcosxdx= \int_{0}^{\frac{\pi}{6}} \sin ^{2} x \cos x d x= ∫06πsin2xcosxdx= কত ?
