Let $S$ be the array of integral points $(x, y, z)$ with $x = 0, 1, 2; y = 0, 1, 2, 3$ and $z = 0, 1, 2, 3, 4$. If two points are chosen from $S$, then the probability that their mid point is in $S$ is

Probability of any event $x$ lies

The probability that $A, B$ and $C$ can solve a problem are $\displaystyle \frac{4}{5}, \frac{2}{3}$ and $\dfrac{3}{7}$ respectively. The probability of the problem being solved by $A$ and $B$ is $\dfrac{8}{15}$, $B$ and $C$ is $\dfrac{2}{7}$, $A$ and $C$ is $\dfrac{12}{35}$. The probability of the problem being solved by all the three is $\dfrac{8}{35}$.

Find the probability that the problem can be solved by at least one of them.

If $P(A)-p(A')=0.5$, then $P(A)=$____

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