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Resistance of 2 Ω2\ \Omega and 3 Ω3\ \Omega are connected in series. If the potential difference across the 2 Ω2\ \Omega resistor is 3 V3\ V, the potential difference across 3Ω3\Omega is:

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Given,

Resistors of resistances, R1=2 ΩR_1=2\ \Omega and R2=3 ΩR_2=3\ \Omega are connected in series.

Potential difference across 2 Ω2\ \Omega resistor, V1=3 VV_1=3\ V

Potential difference across 2 Ω2\ \Omega resistor, V2V_2

According to Ohm's law,

V=IRV=IR

    I=VR\implies I=\dfrac VR

    I=V1R1\implies I=\dfrac {V_1}{R_1}

I=32I=\dfrac {3}{2}

I=1.5 AI=1.5\ A

We know, current in a series circuit remains constant.

V2=IR2V_2=IR_2

V2=1.5×3V_2=1.5\times 3

V2=4.5 VV_2=4.5\ V

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