1.1. By taking logarithms (base $e$) of both sides show that the equation

$y=A{e}^{kx}$

can be written in the form $lny=kx+lnA$

1.2. Hence ...

(i) write the equation $y=2{e}^{0.01x}$ in the form $lny=kx+lnA$.

(ii) write the equation $lny=0.3x+In5$ in the form $y=A{e}^{kx}$.