মান নির্ণয়
tanA.tan(60°+A).tan(120°+A)=?\tan{A}.tan (60°+A).tan(120°+A)=? tanA.tan(60°+A).tan(120°+A)=?
3\sqrt3 3
- tan3A \tan{3A} tan3A
tan23A \tan^2{3A} tan23A
None None None
tanA.tan(60°+A)tan{180°−(60°−A)}=−tanA.tan(60°+A).tan(60°−A)=−tanA.tan60°+tanA1−tan60°tanA.tan60°−tanA1+tan60°.tanA=−tanA3+tanA1−3tanA.3−tanA1+3tanA=−tanA3−tan2A1−3tan2A=−3tanA−tan3A1−3tan2A=−tan3A \tan{A}.tan(60°+A)tan\{180°-(60°-A)\} \\ =-tanA.tan(60°+A).tan(60°-A)\\ =-tanA.\frac{tan60°+tanA}{1-tan60°tanA}.\frac{tan60°-tanA}{1+tan60°.tanA} \\ =-\tan{A}\frac{\sqrt3+\tan{A}}{1-\sqrt3\tan{A}}.\frac{\sqrt3-\tan{A}}{1+\sqrt3\tan{A}} \\ =-\tan{A}\frac{3-\tan^2{A}}{1-3\tan^2{A}}\\ =-\frac{3\tan{A}-\tan^3{A}}{1-3\tan^2{A}}=-\tan{3A}\ tanA.tan(60°+A)tan{180°−(60°−A)}=−tanA.tan(60°+A).tan(60°−A)=−tanA.1−tan60°tanAtan60°+tanA.1+tan60°.tanAtan60°−tanA=−tanA1−3tanA3+tanA.1+3tanA3−tanA=−tanA1−3tan2A3−tan2A=−1−3tan2A3tanA−tan3A=−tan3A
প্রমাণ কর যে, sin75∘+sin15∘sin75∘−sin15∘=3 \frac{\sin 75^{\circ}+\sin 15^{\circ}}{\sin 75^{\circ}-\sin 15^{\circ}}=\sqrt{3} sin75∘−sin15∘sin75∘+sin15∘=3.
tanθ=p হলে, cos2θ= কত? \tan \theta=p \text { হলে, } \cos 2 \theta=\text { কত? } tanθ=p হলে, cos2θ= কত?
যদি π2<θ<πএবংsinθ=35হয়, \frac{\pi}{2} < \theta < \pi এ ব ং \sin{\theta} = \frac{3}{5} হ য় , 2π<θ<πএবংsinθ=53হয়, তবে cosθ এর মান কত?
sin A + cos A = sin B + cos B হলে A + B =?