$\mathrm{A}(\mathrm{a}+1,1), \mathrm{B}(2 \mathrm{a}+1,3), \mathrm{C}(2 \mathrm{a}+2,2 \mathrm{a})$ একটি ত্রিভুজের তিনটি শীর্ষবিন্দু।

$a=3$ হলে, $ABC$ ত্রিভুজের ক্ষেত্রফল কত বর্গ একক?

Let A(-4, 0) & B(4,0). Then the number of points C=(x,y) on the circle ${x^2} + {y^2} = 16$ lying in first quadrant $(x,y \geqslant 0)$ such that the area of the triangle whose vertices are A,B,C is a integer is 

A triangle has two of its vertices at (0, 1) and (2, 2) in the cartesioan plane. Its third vertex lies on the x-axis. If the area of the triangle is 2 square units then the sum of the possible abscissae of the third vertex, is -