The equation of the circle which circumscribes the triangle formed by the lines x + y + 3 = 0, x - y + 1 =0 and x = 3 is

Equation of a circle whose centre is in $I$ quadrant as $\left(\alpha,\ \beta\right)$ and touches $x-$axis will be:

$x^{2}+y^{2}+a y=0$ এর পোলার সমীকরণ কোনটি?

  $r^{2} - 2 r \cos{\theta} - 2 r \sin{\theta} - 5 = 0$  বৃত্তের কেন্দ্র নিচের কোনটি ?

The radius of circle $x^2+y^2-6x-8y=0$