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The equation of the parabola with vertex at (0, 0), axis along x-axis and passing through (53,103)\displaystyle \left( \frac{5}{3}, \frac{10}{3} \right) is

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The equation of a parabola whose vertex is

at (0,0)(0,0) and the axis is along x-axis

y2=±4ax y^{2} = \pm 4ax

as the curve goes through The point

(5/3,10/3) (5/3,10/3)

So, the curve is y2=4ax y^{2} = 4ax

(10/3)2=4.a(5/3) \therefore (10/3)^{2} = 4.a(5/3)

100=4.a.15 100 = 4.a.15

a=5/3 a = 5/3

\therefore The curve is y2=4.5/3.x y^{2} = 4.5/3.x

3y2=20x \therefore 3y^{2} = 20x [Ans]

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