তাপীয় সূত্র

The molar specific heat at constant pressure for a monoatomic gas is ;

হানি নাটস

Molar-specific heat at constant pressure for a monoatomic gas is to be calculated.

For monoatomic gas, dof =3 =3 [dof is the degrees of fredom]

Now, x=1+2dof x=1+\frac{2}{d o f}

γ=1+23=5/3 \therefore \gamma=1+\frac{2}{3}=5 / 3 \text {. }

Now, cv=Rγ1=R5/31=3R2 \quad c_{v}=\frac{R}{\gamma-1}=\frac{R}{5 / 3-1}=\frac{3 R}{2}

Cp=R+3R2=5R2[AS1CpCV=R]CP=5R2 \begin{array}{l} \therefore C_{p}=R+\frac{3 R}{2}=\frac{5 R}{2} \quad\left[A S_{1} C_{p}-C_{V}=R\right] \\ C_{P}=\frac{5 R}{2} \end{array}

Correct answer- option - B

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