The point which does not belong to the feasible region of the LPP:

Minimize: $Z=60x+10y$

subject to $3x+y \ge 18$

$2x+2y \ge 12$

$x+2y\ge 10$

$x,y \ge 0$ is

We test whether the inequalitiies are satisfied or not

$(0,8)$, $3(0)+8 \ge 8$ $8\ge 8$ is true.

$2(0)+2(8)=16\ge 12$ is true.

$0+2(8)=16 \ge 10$ is true.

$\therefore$ $(0,8)$ is in the feasible region.

$(4,2)$, $3(4)+2=14 \ge 8$

$2(4)+2(2)=16\ge 12$

$4+2(2)=8\ge 10$ is not true

$\therefore$ $(4,2)$ is not a point in the feasible region

$\therefore$ (2) is correct