জ্যামিতিক আলোকবিজ্ঞান

The power of a diverging lens is 10D and that of a converging lens is 6D. When these two lenses are placed in contact with each other. The power of their combination will be

হানি নাটস

The focal length of diverging lens is

F1=1P=110{ F }_{ 1 }=\dfrac { 1 }{ P } =-\dfrac { 1 }{ 10 }

The focal length of converging lens is

F2=1P=+16{ F }_{ 2 }=\dfrac { 1 }{ P } =+\dfrac { 1 }{ 6 }

The focal length of combined lens is

1f=1f1+1f2\dfrac { 1 }{ f } =\dfrac { 1 }{ { f }_{ 1 } } +\dfrac { 1 }{ { f }_{ 2 } }

P=1f=10+6=4DP=\dfrac { 1 }{ f } =-10+6=-4D

The combined lens will act as diverging (concave ) lens.

Option C is correct.

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