The value of $g$ at the surface of earth is $9.8\ m/s^{2}$ then the value of $'g'$ at a place $480\ km$ above the surface of the earth will be nearly (radius of the earth is $6400\ km)$.

Given that,

$g=9.8\,m/{{s}^{2}}$

$h=480\,km$

$R=6400\,km$

We know that,

$g'=g\left( 1-\dfrac{2h}{R} \right)$

$g'=9.8\left( 1-\dfrac{2\times 480}{6400} \right)$

$g'=8.33\,m/{{s}^{2}}$

Hence, the value of g’ is $8.33\,m/{{s}^{2}}$.