সংঘর্ষ

Total impulse imposed by ball of mass 2 kg to the ball of mass 4 kg has the magnitude equal to

হানি নাটস

Applying Momentum Conservation

4×10+2×8=4v1+2v2.2v1+v2=28(1) \begin{aligned} 4 \times 10+2 \times 8 & =4 v_{1}+2 v_{2} . \\ 2 v_{1}+v_{2} & =28-(1) \end{aligned}

As the coefficient of restitution

v2v1108=1v2v1=2(i1) \begin{array}{l} \frac{v_{2}-v_{1}}{10-8}=1 \\ v_{2}-v_{1}=2-(i 1) \end{array}

By equation (1) and (ii)

3v1=26v1=263 m/sv2=323 m/s. \begin{array}{r} 3 v_{1}=26 \\ \Rightarrow \quad v_{1}=\frac{26}{3} \mathrm{~m} / \mathrm{s} \\ v_{2}=\frac{32}{3} \mathrm{~m} / \mathrm{s} . \end{array}

Impulse by mass 4 kg=4(10263)=4×43 4 \mathrm{~kg}=4\left(10-\frac{26}{3}\right)=\frac{4 \times 4}{3}

=5.3NS =5.3 N_{S}

option B is correct.

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