Under the action of a force, a 2kg mass moves such that its position x as a function of time t is given by $x=t^3/3$ ;where x is in meters and t in second. The work done by the force in first two seconds is:

The force constant of a wire is k and that of another wire is $2k$When both the wires are stretched through same distance, then the work done.

The force on a particle as the function of displacement x(in x-direction) is given by $F=10+0.5x$

The work done corresponding to displacement of particle from $x=0$ to $x=2$ unit is?

A body of mass travels in a straight line with a velocity $v=kx^{3/2}$ where $k$ is a constant. The work done in displacing the body from $x=0$ to $x$ is proportional to:

A body is acted upon by a force which is proportional to the distance covered. If distance covered by denoted by x, then work done by the force will be proportional to: