1. There are only $r$ red counters and $g$ green counters in a bag.

A counter is taken at random from the bag.
The probability that the counter is green is $\frac{3}{7}$.

The counter is put back in the bag.

2 more red counters and 3 more green counters are put in the bag.
A counter is taken at random from the bag.

The probability that the counter is green is $\frac{6}{13}$
Find the number of red counters and the number of green counters that were in the bag originally.