কৃতকাজ

What is the work done by 0.20.2 mole of a gas at room temperature to double volume during isobaric process (take R=2cal mol1K1R=2 cal \ mol^{-1} K^{-1})

হানি নাটস

Work done W=P(VfVi)=P(2VV)=PVW = P(V_f-V_i) = P(2V-V) = PV

So, we know that the work done W=PV=nRTW = PV =nRT

W=0.2×2×300=120 calW=0.2\times2\times300=120\ cal

Where nn is the mole of gas, TT is the temperature,

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