Let $f(x)=2-|x-3|, 1 \le x \le 5$ and for rest of the values $f(x)$ can be obtained by using the relation $f(5x)=\alpha\, f(x)\forall\, x \in R$.
The value of $f(2007)$ taking $\alpha = 5$, is: 

Let for $a\neq { a }_{ 1 }\neq 0$
$f(x)={ ax }^{ 2 }+bx+c,g(x)={ a }_{ 1 }{ x }^{ 2 }+{ b }_{ 1 }x+{ c }_{ 1 }$ and $p(x)=0$ only for x = -1 and p(-2) = 2, the the value of p(2) is :

$f: \mathrm{R} \rightarrow \mathrm{R}$ (ে $f(\mathrm{x})=\left\{\begin{array}{l}\mathrm{x}^{2}+3 \mathrm{x}, \text { यখन } \mathrm{x} \geq 2 \\ x+2, \text { यখन } \mathrm{x}<2\end{array}\right.$ হলে,

(i) f(2) এর মান=4;  (ii) f(-2) এর মান =0;  (iii) f(3) এর মান=18

নিচের কোনটি সঠিক ?

For a function F, F(0) = 2, F(1) = 3, F(x + 2) = 2 F(x) - F(x + 1) for x $\geq$ 0, then F(5) is equal to-