যদি y= sin^-1x  হয়, তবে y₁/y₂ এর মান কোনটি? 

$\begin{array}{c}y=\sin ^{-1} x \Rightarrow y_{1}=\frac{1}{\sqrt{1-x^{2}}} \\ y_{2}=\frac{\sqrt{1-x^{2}} \times 0-1 \frac{1}{2 \sqrt{1-x^{2}}} \times(-2 x)}{\left(1-x^{2}\right)}=\frac{x}{\left(1-x^{2}\right)\left(\sqrt{1-x^{2}}\right)} \\ \therefore \frac{y_{1}}{y_{2}}=\frac{1}{\sqrt{1-x^{2}}} \times \frac{\left(1-x^{2}\right)\left(\sqrt{1-x^{2}}\right)}{x}=\frac{1-x^{2}}{x}=\frac{1}{x}-\frac{x^{2}}{x}=\frac{1}{x}-x\end{array}$