প্রতিবিম্ব

A converging beam of rays is incident on a diverging thin lens. Having passed through the lens the ray intersect at a point 15 cm from the lens. If lens is removed the point where the rays meet will move 5 cm closer towards the mounting that holds the lens. The focal length of lens is

হানি নাটস

v=+15v= +15 ; u=+10u= +10

1v1u=1f\dfrac{1}{v}-\dfrac{1}{u}=\dfrac{1}{f}

115110=1f\dfrac{1}{15}-\dfrac{1}{10}=\dfrac{1}{f}

f=30f= -30

option CC is correct

প্রতিবিম্ব টপিকের ওপরে পরীক্ষা দাও