A force $\vec { F }=(3t\hat { i } +5\hat { j })$N acts on a body due to which its position varies as $\vec { S }=(2{t^2}\hat { i } -5\hat { j })$. Find the work done by this force in initial $2s$.

The force constant of a wire is k and that of another wire is $2k$When both the wires are stretched through same distance, then the work done.

The force on a particle as the function of displacement x(in x-direction) is given by $F=10+0.5x$

The work done corresponding to displacement of particle from $x=0$ to $x=2$ unit is?

The displacement x of a particle moving in one dimension under the action of a constant force is related to the time t by the equation $t = \sqrt { x} +3$ where x is in meters and t is in seconds . the work done by the force in the first $6$ second is

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