A network of resistances, cell and capacitor $C(=2\mu F)$ is shown in adjoining figure. In steady state condition, the charge $2\mu F$ capacitor is $Q$. while $R$ is unknown resistance. Values of $Q$ and $R$ are respectively

In the steady state, current through capacitor

Using Kirchhof's voltage law to the circuit ACD

In ACD ,$V_1+V_2+V_3+V_4=0$

We have, $10-2+1\times R+1\times2 =0$

Or $R=10\Omega$

Potential difference across C and D

$V_C-V_D=2×1= 2V$

As, $V_D=0V$

So, $V_C=2V$

Potential difference across capacitor

$=4-2=2V$

$\therefore$ Charge on capacitor $Q=CV=2\mu F \times 2=4\mu C$