প্রতিবিম্ব

A wild rose 1.2 cm in diameter is 90.0 cm from a camera's zoom lens. The focal length of the lens has a magnitude of 150.0 mm.What is the distance between the lens and the camera film where the image of the rose is formed? 

IUT 16-17

Solution: (b) ;1u+1v=1fV=18.0 cm ; \frac{1}{\mathrm{u}}+\frac{1}{\mathrm{v}}=\frac{1}{\mathrm{f}} \therefore \mathrm{V}=18.0 \mathrm{~cm} (Ans.)

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