The $5$th term in the expansion of $\left(2x^2 + \dfrac{3}{x}\right)^5$ is

we k.n.t $(r+1)^{th}$ term in expansion of $(a+b)^n$ is $^nc_ra^{n-r}b^r$

$\Rightarrow T_{r+1}=^nc_ra^{n-r}b^r$

Here $a=2x^2$ and $b=\dfrac{2}{x}$ and $n=5$

5th term = $T_5=^5c_4a^{5-4}b^4=5ab^4=5(2x^2)(\dfrac{3}{x})^4=(5*2*3^4)(x^{2-4}=810x^{-2}$

$\therefore$ The $5$th term in expansion of $(2x^2+\dfrac{3}{x})^4$ is $810x^{-2}$.