((3x)/2-2/(3x^2))^11

এর বিস্তৃতিতে x⁵ এর সহগ কত?

$\begin{array}{l} \text { } T_{(r+1)}={ }^{11} C_{r} \cdot\left(\frac{3}{2}\right)^{11-2 r} x^{11-r} \cdot\left(\frac{-2}{3}\right)^{r} \cdot x^{-2 r} \\ ={ }^{11} C_{r} \cdot 3^{11-2 r} \cdot 2^{-11+2 r} \cdot(-1)^{r} \cdot x^{11-3 r} \\ \text { প্রশ্নমতে, } 11-3 r=5 \therefore r=2 \\ \therefore \mathrm{T}_{(2+1)}={ }^{11} \mathrm{C}_{2} \cdot 3^{11-4} \cdot 2^{-11+2.2}: \mathrm{x}^{5} \\ =\frac{120285}{128} x^{5} \\ \end{array}$