A curve is such that the area of the region bounded by the coordinates axes, the curve and the ordinate of any point on it is equal to the cube of that ordinate the curve represent.

$Letf(x)={ sin }^{ -1 }(sin\quad x)+{ cos }^{ -1 }(\quad cos\quad x),\quad g(x)=mx\quad and\quad h(x)=x\quad$ are three functions. Now g(x) is divided area between f(x),x=$\pi$ and y=0 into two equal parts.

The area bounded by the curve y=f(x), x=$\pi$ and y=0 is:

Semicircles are drawn outside by taking every side of regular hexagon as a diameter. The ;perimeter of hexagon is 60 cm. Find the area of complete figure formed as such.($\pi$ = 3.14) ($\sqrt3$ = 1.73)

The area ehclosed by the curves y = f(x) and ; y =g(x), where f(x) = max ${x , x^2}$ and g(x) = min ${x, x^2}$ opver the interval [0,1] is& ;

The area of the closed figure bounded by $x=-1, \, x=2$ and $y= -x^2+2, \, x\leq 1$ and $y= 2x-1 ,\, x>1$ and the abscissa axis is ;