ধারা
Let n be a positive integer. Then the value of ∑k=0n(−1)k(nk) \sum_{k = 0}^{n} \left ( - 1 \right )^{k} \left ( \frac{n}{k} \right ) ∑k=0n(−1)k(kn) is --
- 1
0
1
None of them
(b);∑k=0n(−1)k(nk)=(1−1)n=0 (\mathrm{b}) ; \sum_{\mathrm{k}=0}^{\mathrm{n}}(-1)^{\mathrm{k}}\left(\begin{array}{l}\mathrm{n} \\ \mathrm{k}\end{array}\right)=(1-1)^{\mathrm{n}}=0 (b);∑k=0n(−1)k(nk)=(1−1)n=0
Find the sum of the series ∑r=0n(−1)nnCr[12r+3r22r+7r23r+15r24r+...upto m terms]\displaystyle\sum _{ r=0 }^{ n }{ { \left( -1 \right) }^{ n } } { _{ }^{ n }{ C } }_{ r }\left[ \cfrac { 1 }{ { 2 }^{ r } } +\cfrac { { 3 }^{ r } }{ { 2 }^{ 2r } } +\cfrac { { 7 }^{ r } }{ { 2 }^{ 3r } } +\cfrac { { 15 }^{ r } }{ { 2 }^{ 4r } } +...upto\: m\: terms \right] r=0∑n(−1)nnCr[2r1+22r3r+23r7r+24r15r+...uptomterms]
The arithmetic mean of nC0, nC1, nC2...., nCn^nC_0 , \ ^nC_1, \ ^nC_2 ...., \ ^nC_nnC0, nC1, nC2...., nCn is ;
Number of different terms in the sum (1+x)2009⋅(1+x2)2008+(1+x3)2007, ( 1 + x ) ^ { 2009 } \cdot \left( 1 + x ^ { 2 } \right) ^ { 2008 } + \left( 1 + x ^ { 3 } \right) ^ { 2007 } , (1+x)2009⋅(1+x2)2008+(1+x3)2007, is
Find the value of 1(n−1)!+1(n−3)!3!+1(n−5)!5!+...\dfrac{1}{\left(n-1\right)!}+\dfrac{1}{\left(n-3\right)!3!}+\dfrac{1}{\left(n-5\right)!5!}+...(n−1)!1+(n−3)!3!1+(n−5)!5!1+...